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Old 07-01-2002, 08:02 PM   #1
72chevyLWB
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LED/ electrical ?

I have an LED bar from a 98 S-10 3rd brake light. Now, these lights are in series right? So can I just cut off which ones I don't need because its too tall. I am going to do 2 or 3 rows of LED's in each tail light going up and down. I just need to find out how to trim them down. Heres a pic of the printed circuit.
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Old 07-01-2002, 08:03 PM   #2
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Old 07-01-2002, 08:17 PM   #3
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They should be in series. You could also get a bare board with no cicuitryor holes in it and cut it to fit, and build your own. Not that hard. That way you could integrate an led turn signal with a split in the board, and different colored lights.
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Old 07-01-2002, 08:22 PM   #4
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But I'm a cheap A#$ and this looks like a cheaper alternative. I have this one plus one more coming off one of our builders. I would wire up just the outside one to blink and all of them for the brake. Figure something out.
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Old 07-01-2002, 08:36 PM   #5
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They should be in parallel, not series. If they were in series, they'd go from very bright to very dim since each light would eat a bit more voltage as the electricity moved down the line.

Series is like the small Christmas lights (the infamous, "If one goes out, they all go out!"). Parallel is like the big lights (the bulbs screw in). Your dash lights are in parallel.
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Old 07-01-2002, 08:42 PM   #6
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okay, so now what
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Old 07-01-2002, 09:57 PM   #7
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series is for constant current and parallel is for constant voltage.
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Old 07-01-2002, 10:00 PM   #8
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If you place resistors and small capicitors in the beginning and the end of the series like ford has done on there LED's then it keeps a constant rate of energy to all the bulbs.
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Old 07-01-2002, 11:02 PM   #9
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Why? If they're in parallel, you already have constant voltage. Adding resistance is just going...

Wait a minute. Do those LEDs take a full 12V (I would think so, but then again I think in incandescent bulbs) or do they take 5V like an ECM & all its sensors? If they took 5V, I could see why resistors would help.
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Old 07-01-2002, 11:05 PM   #10
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i THINK most LEDs take 9 volts.
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Old 07-01-2002, 11:52 PM   #11
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They are in parallel...
Most LEDs take 2~4 volts, too much voltage and they will
burn out quickly. I am not familiar with the circuit shown,
but when removing extra LEDs, for each LED removed you
can count on approx 20mA extra going to each LED left.
There may be a voltage regulator, and/or resistors mounted
on the back, ie, surface mount compontents. Most likey,
removing one or two, no problem, more than that and you
may end up with all the LED failing rather quickly depending
upon the design. Best way to determine the current draw
is to use an ammeter on the entire unit, then divide the amps
by number of LEDs. If you remove quite a few of the LEDs,
you may have to install resistors to make up to the current
flow that those LEDs provided for, or else, you'll experience
the entire unit failing to light...If you need more help, just
e-mail me offline, will be glad to help you make it work.
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Old 07-02-2002, 12:12 AM   #12
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Ahhh! Makes sense now.
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Old 07-02-2002, 09:05 AM   #13
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Yeah but they sound really cool when they blow up. Like a little firecracker!
They may actually be both series and parrallel in groups. Remember, all 12+ volts must be consumed by the components in the series portion of the curcuit (ie, 6 LEDs divided into 12 equals 2vdc each LED. 4 LEDs divided into 12 equals 3vdc). If you cut some LED's out, either eliminate the entire series (if it's one of several groups) or add a resistor to replace the drop from the LED's. Hope this helps.
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